1 条题解
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0
C :
#include<stdio.h> #include<string.h> int map[21][21] = {0}, vis[21] = {0}, n, flag = 0, m; void dfs(int start, int num) { int i; if( num == n - 1 && start == n) flag=1; if(flag==1) return; for(i=2;i<=n;++i) if(vis[i]!=1&&map[start][i]!=0){ vis[i]=1; dfs(i,num+1); vis[i]=0; } } int main() { while(scanf("%d%d", &n, &m) != EOF) { int i, j; memset(map, 0, sizeof(map)); memset(vis, 0, sizeof(vis)); for( i = 0; i < 21; i++) { vis[i] = 0; for( j = 0; j < 21; j++) map[i][j] = 0; } flag = 0; while(m--) { int a, b; scanf("%d%d", &a, &b); map[a][b] = 1; map[b][a] = 1; } dfs(1, 0); if(flag) printf("1\n"); else printf("0\n"); } return 0; }
C++ :
#include <cstdio> #include <vector> using namespace std; int ed, n; vector < vector < int > > v; bool dfs(int x, int s) { if (s == ed) return x == n - 1; for (vector < int >::iterator it = v[x].begin(); it != v[x].end(); ++it) if (~s >> *it & 1) if (dfs(*it, s | (1 << *it))) return true; return false; } int main() { int m; while (EOF != scanf("%d%d", &n, &m)) { v = vector < vector < int > >(n); ed = (1 << n) - 1; while (m--) { int x, y; scanf("%d %d", &x, &y); --x; --y; v[x].push_back(y); v[y].push_back(x); } printf("%d\n", dfs(0, 1)); } return 0; }
- 1
信息
- ID
- 1014
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者