1 条题解
-
0
C++ :
#include <iostream> #include <cstring> #define MAX 6 #define MOD 1000000007 #define ll long long using namespace std; int reverse[6]={3,4,5,0,1,2}; struct matrix { int n; ll d[MAX][MAX]; matrix(){memset(d, 0, sizeof(d));} }; matrix operator *(const matrix &m1, const matrix &m2) { matrix res; res.n = m1.n; for(int i = 0; i < m1.n; i++) for(int j = 0; j < m1.n; j++) for(int k = 0; k < m1.n; k++) { res.d[i][j] += m1.d[i][k] * m2.d[k][j]; res.d[i][j] %= MOD; } return res; } matrix operator ^(const matrix &m, ll n) { matrix res; res.n = m.n; for(int i = 0; i < res.n; i++) res.d[i][i] = 1; matrix tmp = m; while(n) { if(n & 1) res = res * tmp; tmp = tmp * tmp; n >>= 1; } return res; } ll pow(ll n, ll m) { ll ans = 1; while(m) { if(m & 1) ans = (ans * n) % MOD; m >>= 1; n = (n * n) % MOD; } return ans; } int main() { int n, m, a, b; while(cin >> n >> m) { matrix mat; mat.n = 6; for(int i = 0; i < 6; i++) for(int j = 0; j < 6; j++) mat.d[i][j] = 1; for(int i = 0; i < m; i++) { cin >> a >> b; a--;b--; mat.d[a][reverse[b]]=mat.d[b][reverse[a]]=0; } mat = mat ^ (n - 1); ll ans = 0; for(int i = 0; i < 6; i++) for(int j = 0; j < 6; j++) ans = (ans + mat.d[i][j]) % MOD; cout << (ans * pow(4, n)) % MOD << endl; } return 0; }
- 1
信息
- ID
- 1174
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者