1 条题解
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0
C :
#include <stdio.h> int main(){ int mm; int y,m,d; int sum; int tmp; int num[12] = {0,31,28,31,30,31,30,31,31,30,31,30}; scanf("%d",&mm); while (mm--) { scanf("%d%d%d",&y,&m,&d); sum = d; if (y%400==0||(y%4==0&&y%100!=0)) { num[2] = 29; } else { num[2] = 28; } for (int i = 1;i<m;i++) { sum = sum + num[i]; } printf("%d\n",sum); } }
C++ :
#include <iostream> #include <cstdio> using namespace std; int month[13]= {0,31,0,31,30,31,30,31,31,30,31,30,31}; int check(int y) { if (y % 100 == 0) return y % 400 == 0; else return y % 4 == 0; } int main() { //freopen("test.in", "r", stdin); //freopen("test.out", "w", stdout); int y, m, d, t; cin >> t; while (t--) { int sum = 0; cin >> y >> m >> d; month[2] = check(y) + 28; for(int i = 1; i < m; i++) sum = sum + month[i]; sum = sum + d; cout << sum << endl; } return 0; }
Java :
import java.io.*; import java.util.*; public class Main { public static void main(String g[])throws Exception { int t,y,m,d,sum; Scanner cin= new Scanner(System.in); t=cin.nextInt(); for(int i=0;i<t;i++) { sum=0; y=cin.nextInt(); m=cin.nextInt(); d=cin.nextInt(); for(int j=1;j<m;j++) switch(j) { case 1: sum+=31; break; case 2: if((y%4==0&&y%100!=0)||y%400==0) sum+=29; else sum+=28; break; case 3: sum+=31; break; case 4: sum+=30; break; case 5: sum+=31; break; case 6: sum+=30; break; case 7: sum+=31; break; case 8: sum+=31; break; case 9: sum+=30; break; case 10: sum+=31; break; case 11: sum+=30; break; case 12: sum+=31; break; } System.out.println(sum+d); } } }
- 1
信息
- ID
- 1377
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者