1 条题解

  • 0
    @ 2024-12-24 9:59:19

    C :

    #include<stdio.h>
    int main(void)
    {int a,b,c,i;
    int k[10],j[10];
    a=b=c=0;
    for(i=1;i<=3;i++)
    scanf("%d%d",&k[i],&j[i]);
    a=k[1]/j[1];
    if(k[1]%j[i]!=0)
    a=a+1;
    b=k[2]/j[2];
    if(k[2]%j[2]!=0)
    b=b+1;
    c=k[3]/j[3];
    if(k[3]%j[3]!=0)
    c=c+1;
    if(a==1)
    printf("Alpha will be back in %d day.\n",a);
    else
    printf("Alpha will be back in %d days.\n",a);
    if(b==1)
    printf("Bob will be back in %d day.\n",b);
    else
    printf("Bob will be back in %d days.\n",b);
    if(c==1)
    printf("Cindy will be back in %d day.\n",c);
    else
    printf("Cindy will be back in %d days.\n",c);
    
    
    	
    }
    

    C++ :

    #include<stdio.h>
    int main()
    {
    	int a1,b1,a2,b2,a3,b3,c1,c2,c3;
    	scanf("%d%d%d%d%d%d",&a1,&b1,&a2,&b2,&a3,&b3);
    	if(a1%b1==0)c1=a1/b1;
    	else c1=a1/b1+1;
    	if(a2%b2==0)c2=a2/b2;
    	else c2=a2/b2+1;
    	if(a3%b3==0)c3=a3/b3;
    	else c3=a3/b3+1;
    	if(c1!=1)
    	printf("Alpha will be back in %d days.\n",c1);
    	else
    	printf("Alpha will be back in %d day.\n",c1);
    	if(c2!=1)
    	printf("Bob will be back in %d days.\n",c2);
    	else
    	printf("Bob will be back in %d day.\n",c2);
    	if(c3!=1)
    	printf("Cindy will be back in %d days.\n",c3);
    	else
    	printf("Cindy will be back in %d day.\n",c3);
    	return 0;
    }
    
    
    • 1

    信息

    ID
    1423
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者