1 条题解
-
0
C :
#include<stdio.h> int main(void) {int a,b,c,i; int k[10],j[10]; a=b=c=0; for(i=1;i<=3;i++) scanf("%d%d",&k[i],&j[i]); a=k[1]/j[1]; if(k[1]%j[i]!=0) a=a+1; b=k[2]/j[2]; if(k[2]%j[2]!=0) b=b+1; c=k[3]/j[3]; if(k[3]%j[3]!=0) c=c+1; if(a==1) printf("Alpha will be back in %d day.\n",a); else printf("Alpha will be back in %d days.\n",a); if(b==1) printf("Bob will be back in %d day.\n",b); else printf("Bob will be back in %d days.\n",b); if(c==1) printf("Cindy will be back in %d day.\n",c); else printf("Cindy will be back in %d days.\n",c); }
C++ :
#include<stdio.h> int main() { int a1,b1,a2,b2,a3,b3,c1,c2,c3; scanf("%d%d%d%d%d%d",&a1,&b1,&a2,&b2,&a3,&b3); if(a1%b1==0)c1=a1/b1; else c1=a1/b1+1; if(a2%b2==0)c2=a2/b2; else c2=a2/b2+1; if(a3%b3==0)c3=a3/b3; else c3=a3/b3+1; if(c1!=1) printf("Alpha will be back in %d days.\n",c1); else printf("Alpha will be back in %d day.\n",c1); if(c2!=1) printf("Bob will be back in %d days.\n",c2); else printf("Bob will be back in %d day.\n",c2); if(c3!=1) printf("Cindy will be back in %d days.\n",c3); else printf("Cindy will be back in %d day.\n",c3); return 0; }
- 1
信息
- ID
- 1423
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者