1 条题解

  • 0
    @ 2024-12-24 9:59:26

    C :

    #include<stdio.h>
    #include<string.h>
    #include<math.h>
    
    int main()
    {
    	int n,i,t,flag=0,num=0,len,j,k,l;
    	char s[100][105],s1[25],temp[25];
    	scanf("%d",&t);
    	for(i=0;i<t;i++)
    	{
    		num=0;
    		scanf("%d",&n);
    		getchar();
    		gets(s1);
    		
    		for(j=0;j<n;j++)
    			gets(s[j]);
    		for(j=0;j<n;j++)
    		{
    			len=strlen(s[j]);
    			k=0;
    		
    			for(l=0;l<=len;l++)
    			{
    				if(s[j][l]!=' '&& s[j][l]!='\0')
    					temp[k++]=s[j][l];
    				else 
    				{
    					 temp[k]='\0';
    					 if(strcmp(temp,s1)==0)
    						 num++;
    					  k=0;
    				}
    			}
    		}
    		if(num==0) printf("Do not find\n");
    		 else printf("%d\n",num);
    	}
    	
    
    	return 0;
    }
    
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    
    	public static void main(String[] args) {
    	
    		int T,N;
    		String word,sentence;
    		
    		Scanner in = new Scanner(System.in);
    		T = in.nextInt();
    		
    		for(int i=0;i<T;i++){
    			int sum = 0;
    			N = in.nextInt();
    			word = in.next();
    			in.nextLine();
    			for(int j=0;j<N;j++){
    				sentence = in.nextLine();
    				String[] str = sentence.split(" ");
    				for(String s :str){
    					if(s.equals(word)){
    						sum++;
    						break;
    					}
    				}
    			}
    			if(sum>0) System.out.println(sum);
    			else System.out.println("Do not find");
    		}
    	}
    }
    
    
    • 1

    信息

    ID
    1435
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者