1 条题解

  • 0
    @ 2024-12-24 9:59:26

    C :

    #include<stdio.h>
    #include<string.h>
    #include<ctype.h>
    
    int main()
    {
    	int i,n;
    	char c,a[201];
    	while(scanf("%c%*c%s%*c",&c,a)!=EOF)
    	{
    		for(n=i=0;i<strlen(a);i++)
    			if(c==tolower(a[i])||c==toupper(a[i]))
    				n++;
    		printf("%.5f\n",n*1.0/strlen(a));
    	}
    	return 0;
    }
    

    C++ :

    #include<stdio.h>
    #include<string.h>
    #include<ctype.h>
    
    int main()
    {
    	int i,n;
    	char c,a[201];
    	while(scanf("%c%*c%s%*c",&c,a)!=EOF)
    	{
    		for(n=i=0;i<strlen(a);i++)
    			if(c==tolower(a[i])||c==toupper(a[i]))
    				n++;
    		printf("%.5f\n",n*1.0/strlen(a));
    	}
    	return 0;
    }
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    
    	public static void main(String[] args) {
    		Scanner in = new Scanner(System.in);
    		while(in.hasNext()){
    			char c = in.next().charAt(0);
    			if(c<='Z')c = (char) (c-'A'+'a');
    			String s = in.next();
    			int cou = 0;
    			for(int i=0;i<s.length();i++){
    				char tem = s.charAt(i);
    				if(tem<='Z')tem = (char) (tem-'A'+'a');
    				if(tem==c)cou++;
    			}
    				
    			System.out.printf("%.5f\n", (float)cou/(float)s.length());
    		}
    	}
    
    }
    
    
    • 1

    信息

    ID
    1449
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者