1 条题解
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0
C :
int main(int argc, char* argv[]) {int i,n,k; double sum,sum1; while(~scanf("%d%d",&n,&k)) { sum=200;sum1=n; for(i=0;i<20;i++) { if(sum1>=sum)break; sum=sum*(1+k*1.0/100); sum1+=n; } if(i>19)printf("Impossible\n"); else printf("%d\n",i+1); } return 0; }
C++ :
#include <iostream> using namespace std; int main() { int N,K; while(cin>>N>>K) { float price = 200; float earn = N; int year =1; while( earn <price ) { //每年一次循环 if(year>20) { cout<<"Impossible"<<endl; break; } //cout<<"year: "<<year<<"earn:"<<earn<<"price"<<price<<endl; earn += N;//总收入增加 price = price*(1.0+(float)K/100);//房价增加 year++; } if(year<=20) cout<<year<<endl; } return 0; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner shuru = new Scanner(System.in); while(shuru.hasNext()) { int N = shuru.nextInt(); int K = shuru.nextInt(); int flag = 0; for (int i = 0; i<20; i++) { if (N*(i+1) >= 200 * Math.pow(1.0+K/100.0,i)) { System.out.println(i+1); flag = 1; break; } } if (flag == 0) System.out.printf("Impossible\n"); } } }
- 1
信息
- ID
- 1474
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者