1 条题解
-
0
C :
#include<stdio.h> #include<math.h> int main() { int r,w,l,n=0; while(scanf("%d",&r)!=EOF,r) { scanf("%d%d",&w,&l); if(r*2>=sqrt(w*w+l*l)) printf("Pizza %d fits on the table.\n",++n); else printf("Pizza %d does not fit on the table.\n",++n); } return 0; }
C++ :
#include<stdio.h> #include<math.h> int main() { int r,w,l,n=0; while(scanf("%d",&r)!=EOF,r) { scanf("%d%d",&w,&l); if(r*2>=sqrt(w*w+l*l)) printf("Pizza %d fits on the table.\n",++n); else printf("Pizza %d does not fit on the table.\n",++n); } return 0; }
Java :
import java.util.*; public class Main{ public static void main(String[] args){ Scanner in = new Scanner(System.in); int i = 0; while(in.hasNextInt()){ i++; int r = in.nextInt(); if(r==0) break; int w = in.nextInt(); int l = in.nextInt(); int W = (int)Math.pow(w,2); int L = (int)Math.pow(l,2); int R = (int)Math.pow(2*r,2); if(W+L<=R) System.out.println("Pizza "+i+" fits on the table."); else System.out.println("Pizza "+i+" does not fit on the table."); } } }
- 1
信息
- ID
- 1663
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者