1 条题解
-
0
C :
#include<stdio.h> int main() { int n,i; double length=100,high=length/2; scanf("%d",&n); for(i=2;i<=n;i++) { length=length+2*high; high=high/2; } printf("length=%3.4f\nhigh=%1.4f\n",length,high); return 0; }
C++ :
#include<iostream> #include<cstdio> using namespace std; int main() { int n; cin>>n; double h=100,sum=0; for (int i=1; i<=n; i++) { sum+=2*h; h/=2; } printf("length=%.4lf\nhigh=%.4lf\n",sum-100,h); return 0; }
- 1
信息
- ID
- 1774
- 时间
- 1000ms
- 内存
- 12MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者