1 条题解
-
0
C :
/* * ===================================================================================== * * Filename: 902-3.c * * Description: ihahah * * Version: 1.0 * Created: 2013/9/3 0:32:01 * Revision: none * Compiler: gcc * * Author: mdk-vim.cpp-c (mdk), mengdaikun@gmail.com * Company: cjluacm-vim-mdk * * ===================================================================================== */ #include<stdio.h> #include<stdlib.h> #include<string.h> char s[1001]; void reverse(int begin,int end) { while(begin<end) { char temp=s[begin]; s[begin]=s[end]; s[end]=temp; ++begin; --end; } } int main() { //freopen("a.in","r",stdin); while(gets(s)) { int len=strlen(s),begin=0; reverse(0,len-1); int i; for(i=0;i<len;i++) { if(s[i]!=' ') { if(i>0&&s[i-1]==' ') begin=i; else if(i<len-1&&s[i+1]==' ' || i==len-1) reverse(begin,i); } } printf("%s\n",s); } return 0; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner cin = new Scanner(System.in); while(cin.hasNext()) { String str = cin.nextLine(); revString(str); } } public static String revString(String str) { StringBuilder builder = new StringBuilder(); builder.append("begin "); builder.append(str); builder.append(" end"); String []subStrings = builder.toString().split(" "); for(int i= subStrings.length -2 ;i>=2;i-- ){ System.out.print(subStrings[i]+" "); } System.out.println(subStrings[1]); return null; } }
- 1
信息
- ID
- 1850
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者