1 条题解

  • 0
    @ 2024-12-24 10:06:07

    C :

    #include<stdio.h>
    #include<math.h>
    int main()
    {
    	int t,flagx,flagy;
    	double x1,x2,y1,y2,xq,yq;
    	scanf("%d",&t);
    	while(t--)
    	{
    		scanf("%lf%lf%lf%lf",&x1,&y1,&x2,&y2);
    		flagy=x2>x1?1:-1;
    		flagx=y2>y1?-1:1;
    		xq=(x1+x2)/2;
    		yq=(y1+y2)/2;
    		xq+=flagx*sqrt(3)*fabs(y2-y1)/2;
    		yq+=flagy*sqrt(3)*fabs(x2-x1)/2;
    		printf("(%.2f,%.2f)\n",xq,yq);
    	}
    }
    

    C++ :

    #include<stdio.h>
    #include<math.h>
    int main()
    {
    	int t;
    	scanf("%d",&t);
    	while(t--)
    	{
    		double x1,x2,y1,y2,x3,y3,x,y;
    		scanf("%lf%lf%lf%lf",&x1,&y1,&x2,&y2);
    		x=x2-x1;
    		y=y2-y1;
    		x3=x/2-y*sqrt(3)/2+x1;
    		y3=y/2+x*sqrt(3)/2+y1;
    		printf("(%.2f,%.2f)\n",x3,y3);
    	}
    	return 0;
    }
    
    • 1

    信息

    ID
    1990
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者