1 条题解

  • 0
    @ 2024-12-24 10:06:15

    C :

    #include <stdio.h>
    int n, a, i, t;
    int main(void) {
        scanf("%d", &n);
        for (i = 1; i <= n; i++) {
            scanf("%d", &a);
            t += a;
        }
        printf("%d\n%.1f\n", t, t * 1.0 / n);
        return 0;
    }
    

    C++ :

    #include<iostream>
    
    #include<cstdio>
    
    using namespace std;
    
    int main()
    {
    	int n,a;
    	double s;
    	cin>>n;
    	s=0;
    	for (int i=1;i<=n;i++)
    	{
    		cin>>a;
    		s=s+a;
    	}
    	cout<<s<<endl;
    	printf("%.1lf",s/n);
    	return 0;
    }
    

    Python :

    # coding=utf-8
    t = 0
    n = int(input())
    s = input(). split()
    for i in range(0, n) :
        t = t + int(s[i])
    print(t, format(t / n, ".1f"), sep = '\n')
    
    • 1

    信息

    ID
    2488
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者