又一个双倍经验。“计算邮资”

#include<bits/stdc++.h>
#define int long long
#define INF 0x3f3f3f
using namespace std;
int x,zero;
char c;
signed main(){
	cin>>x>>c;
	int ans;
	if(x<=1000){
		if(c=='n')cout<<"8";
		else cout<<"13";
		return 0;
	}
	if(x%500)ans=((x-1000)/500+1)*4+8;
	else ans=((x-1000)/500)*4+8;
	if(c=='y')ans+=5;
	cout<<ans;
	return 0;
}

双倍经验

#include<bits/stdc++.h>
using namespace std;
int main(){
    int m,n;
	char c;
	cin>>m>>c;
	if(m>1000)n=8+ceil((m-1000)/500.0)*4;
	else n=8;
	if(c=='y')n=n+5;
	cout<<n<<endl; 
	return 0; 
}

大开眼界，这不还是计算邮资吗！（数字都不带改的。。。）

#include<bits/stdc++.h>
using namespace std;
int main()
{
	int n,k=8;
	char a;
	cin>>n>>a;
	if(a=='y')
		k+=5;
	if(n>1000)
	{
		n=n-1000;
		k+=n/500*4;
		if(n%500!=0)
		{
			k+=4;
		}
	}
	cout<<k;
	return 0;
}

C++ :

#include<bits/stdc++.h>
using namespace std;
int ans;
int main(){
	int n;
	char y;
	cin>>n>>y;
	if (y=='y') ans+=5;
	n=(n+499)/500;
	if (n<=2) ans+=8;
	else ans+=8+(n-2)*4;
	cout<<ans;
	return 0;
}

Python :

# coding=utf-8
a=int(input())
b=input()
if a<=1000 and b=='n':
    print(8)
if a<=1000 and b=='y':
    print(13)
if a>1000:
    c=a-1000
    d=c//500
    e=d+1
    if b=='n':
       if c%500==0:
           print(8+4*d)
       else:
           print(8+4*e)
    if b=='y':
       if c%500==0:
           print(13+4*d)
       else:
           print(13+4*e)