1 条题解

  • 0
    @ 2024-12-24 10:06:15

    C :

    #include<stdio.h>
    #include<math.h>
    int main()
    {
    	double a,b,c,delt,r1,r2;
    	scanf("%lf%lf%lf",&a,&b,&c);
    	if(b*b-4*a*c>0)
    	{
    		delt=b*b-4*a*c;
    		r1=(-b+sqrt(delt))/(2*a);
    		r2=(-b-sqrt(delt))/(2*a);
    		printf("r1=%7.2lf\nr2=%7.2lf\n",r1,r2);
    	}
    	return 0;
    }
    

    C++ :

    #include <cstdio>
    #include <cmath>
    int main (void)
    {
    	double a,b,c,r1,r2;
    	scanf("%lf%lf%lf",&a,&b,&c);
    	r1=(-b+sqrt(b*b-4*a*c))/(2*a);
    	r2=(-b-sqrt(b*b-4*a*c))/(2*a);
    	printf("r1=%7.2f\n",r1);
    	printf("r2=%7.2f",r2);
    	return 0;
    }
    

    Java :

    import java.util.Scanner;
    
    import static java.lang.Math.sqrt;
    
    public class Main {
        public static void main(String[] args) {
            Scanner sc = new Scanner(System.in);
            double r1, r2;
            double a, b, c;
            a = sc.nextDouble();
            b = sc.nextDouble();
            c = sc.nextDouble();
            r1 = ((-b + sqrt(b * b - (4 * a * c))) / 2 * a);
            r2 = ((-b - sqrt(b * b - (4 * a * c))) / 2 * a);
            if ((b * b - (4 * a * c)) >= 0) {
                System.out.printf("r1=%7.2f\nr2=%7.2f", r1, r2);
            } else {
                System.out.printf("No real roots!");
            }
            System.out.print("\n");
        }
    }
    
    
    • 1

    信息

    ID
    2508
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者