1 条题解
-
0
C :
#include <stdio.h> int main() { int w; int i; int flag; while(~scanf("%d",&w)) { flag = 0; for(i = 2;i < w;i += 2) if(i % 2 == 0 && (w - i) % 2 == 0) { flag = 1; } if(flag) printf("YES\n"); else printf("NO\n"); } return 0; }
C++ :
#include<cstdio> #include<cstdlib> #include<cstring> #include<cctype> #include<cmath> #include<algorithm> #include<iostream> #include<string> #include<vector> #include<bitset> #include<queue> #include<stack> #include<list> #include<map> #include<set> #define TEST #define LL long long #define Mt(f, x) memset(f, x, sizeof(f)); #define rep(i, s, e) for(int i = (s); i <= (e); ++i) #ifdef TEST #define See(a) cout << #a << " = " << a << endl; #define See2(a, b) cout << #a << " = " << a << ' ' << #b << " = " << b << endl; #define debug(a, s, e) rep(_i, s, e) {cout << a[_i] << ' ';} cout << endl; #define debug2(a, s, e, ss, ee) rep(i_, s, e) {debug(a[i_], ss, ee)} #else #define See(a) #define See2(a, b) #define debug(a, s, e) #define debug2(a, s, e, ss, ee) #endif // TEST const int MAX = 2e9; const int MIN = -2e9; const double eps = 1e-8; const double PI = acos(-1.0); using namespace std; int main() { int n; // freopen("in.txt", "r", stdin); // freopen("out.txt", "w", stdout); while(~scanf("%d", &n)) { if(n == 2) { printf("NO\n"); continue; } printf("%s\n", n % 2 ? "NO" : "YES"); } return 0; }
- 1
信息
- ID
- 842
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者