跑的好快

#include<bits/stdc++.h>
using namespace std;
int main()
{
	int n,m;
	cin>>n>>m;
	int n1=50/n,n2=50/m;
	cout<<n1<<' '<<n2<<endl;
	if(n1==n2)cout<<3;
	else
	{
		cout<<(n>m?1:2);
	}
	return 0;
} 

我相信，我的算法，终有一天，他会将时间复杂度增加到极限

template <class _Tp = const unsigned long long int>
class P { _Tp *p { nullptr }; };
signed WinMain(int argv, char argc[]) {}
#pragma GCC system_header
#include <cstdio>
#include <ctype.h>
typedef unsigned long long ULL;
int add(int a, int b) {
	if (!a) return b;
	return add((a & b) << 1, a ^ b);
}
ULL quick_mul(int a, int b) {
	ULL res = 0;
	for (ULL t = a; b; b >>= 1, t <<= 1)
		if (b & 1) res = add(res, t);
	return res;
}
ULL square(int a) {
	return quick_mul(a, a);
}
int read() {
	char ch;
	int res = 0;
	while (!isdigit(ch = getchar()));
	res = ch ^ 48;
	while (isdigit(ch = getchar())) res = add(quick_mul(res, 10), ch ^ 48);
	return res;
}
int binary_div(int a, int b) {
	int left = -1, right = add(1ll << 31, 0xffffffff);
	while (left + 1 != right) {
		int mid = add(left, right) >> 1;
		if (quick_mul(b, mid) <= a) left = mid;
		else right = mid;
	}
	return left;
}
int mod(int a, int b) {
	return a - quick_mul(binary_div(a, b), b);
}
void print(int a) {
	if (!a) return;
	print(binary_div(a, 10));
	putchar(mod(a, 10) ^ 48);
}
int comp(int a, int b) {
	return add(add(a <= b, a == b), 1);
}
signed main(int argv, char argc[]) {
	int a = read(), b = read();
	print(binary_div(50, a));
	putchar(' ');
	print(binary_div(50, b));
	puts("");
	print(comp(a, b));
	return 0;
}

过于水了吧~~~

直接判断好吧：

#include<iostream>
#define QwQ return 0;
using namespace std;
int n,m;
int main(){
	cin>>n>>m;
	double a=(50.0/n);
	double b=(50.0/m);
	cout<<(int)(a)<<" "<<(int)(b);
	cout<<endl;
	cout<<(a==b?3:a>b?2:1);
	QwQ
}

#include<iostream>
using namespace std;
int n,m;
signed main(){
	cin>>n>>m;
	int x=50/n,y=50/m;
	cout<<x<<' '<<y<<'\n';
	if(x<y)cout<<1;
	else if(x>y)cout<<2;
	else cout<<3;
}

真是神奇，输出int我变成char了（脑梗了）。

#include<bits/stdc++.h>
#define int long long
#define INF 0x3f3f3f
using namespace std;
int n,m;
signed main(){
	cin>>n>>m;
	cout<<50/n<<" "<<50/m<<"\n"<<char((n>m? 49:(n==m? 51:50)));
	return 0;
}

标点符号我恨你 直接理解错误

#include<bits/stdc++.h>
using namespace std;
int main()
{
	int a,b;
	cin>>a>>b;
	double c,d;
	c=50.0/a;
	d=50.0/b;
	cout<<int(c)<<' '<<int(d)<<endl;
	if(int(c)>int(d))
	{
		cout<<2;
	}
	else if(int((c))==int((d)))
	{
		cout<<3;
	}
	else
	{
		cout<<1;
	}
	return 0;
}

Python :

# coding=utf-8
a ,b = input (). split ()
a = int (a)
b = int (b)
a = int (50 / a)
b = int (50 / b)
print (a,b)
if (a < b):
    print ('1')
elif (a > b):
    print ('2')
elif a == b:
    print ('3')

#include<bits/stdc++.h> using namespace std; int main(){ int a,b; cin>>a>>b; cout<<50/a<<" "<<50/b<<endl; if(50/a > 50/b){ cout<<"2"; }else if(50/a == 50/b){ cout<<"3"; }else{ cout<<"1"; } return 0; }